Thread: Newbie problem: 'command not found error'

i enter:

#!/bin/bash
echo "average program: enter 10 numbers mean average"
nm2=1
in 1 2 3 4 5 6 7 8 9 10
do
if test "$1" = "noplay"

exit
fi
if test "$1" = "play"
then
echo -e "\nprint enter number $i"
read nm
nm2=$[nm+nm2]
echo -e "\n$nm2 total"
mean=$[nm2/10]
echo "$mean mean"
fi
if test "$mean" -ge "30" | "$mean" -le "50"
then
echo "your mean in between 30 , 50"
elif test "$mean" -gt "100"
then
echo "your mean greater 100"
else
echo "your mean not in between 30 , 50, or greater 100"
fi
done

runs expected error:

./average.sh: line 19: 0: command not found

'0' in error representation of mean - program runs changes mean changes, error equal $mean.

appreciate padwan learner in search of jedi...please ignore dumb nature of program...

code:

if test "$mean" -ge "30" | "$mean" -le "50"       echo "your mean in between 30 , 50"

you want && in here don't you? want mean greater 30 and less 50.

need 'test' before second test, i.e. if test <expr> && test <expr>.

calculation of running mean wrong, i'm going assume that's because haven't been able test properly.

not quite sure understand point of play/noplay argument. if didn't want play, why run program in first place?

code:

./average.sh noplay

ps. please use code tags (see '#' button in posting toolbar). these preserve indentation.

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